SOLUTION: Name the center,foci,and the vertics of each ellipse whose equation is given
(x-3)^2/25 + (y-4)^2/16 =1
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Question 83900This question is from textbook Algebra and Trigonometry
: Name the center,foci,and the vertics of each ellipse whose equation is given
(x-3)^2/25 + (y-4)^2/16 =1
This question is from textbook Algebra and Trigonometry
Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
The given equation is:
Comparing this to the standard equation, we get:
We find that the centre of the ellipse given by (h,k) is equal to (3, 4)
The foci of the Ellipse is given by (+- ae, 0)
So we first find the eccentricity using the formula:
e =
e =
e = 3/5
So now focus is: (+- ae, 0) = (+ -3, 0)
Now the vertex is (+ - a, 0) = (+- 5, 0)
hence, the solution
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