SOLUTION: find the foci for the conic (x/5)^2-(y/12)^2=1

Question 837668: find the foci for the conic (x/5)^2-(y/12)^2=1

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find the foci for the conic (x/5)^2-(y/12)^2=1
***
This is an equation of a hyperbola with horizontal transverse axis and center at the origin.
Its standard form of equation:
a^2=5^2=25
b^2=12^2=144
c^2=a^2+b^2=25+144=169
c=√169=13
foci: (0�c,0)=(0�13,0)=(-13,0) and (13,0)
RELATED QUESTIONS
what is the center, foci, and asymptotes for the conic?... (answered by ewatrrr)

Identify the type of conic section whose equation is given and find the vertices and... (answered by Fombitz)

For the hyperbola represented by [(y+2)^2]/4 - [x^2]/12=1 find the foci and... (answered by lwsshak3)

find an equations for the conic section that satisfies the given conditions. Hyperbola,... (answered by lwsshak3)

(y+1)^2 = 12(x-1) Graph, including the... (answered by Edwin McCravy)

Find the vertices, foci, asymtopes for y. (y-2)^2/1 - (x-1)^2/4... (answered by lwsshak3)

classify the conic section for (x+3)^2/16 - (y-5)^2/64 = 1 (answered by rapaljer)

Find the foci of the ellipse whose equation is (y^2/16) + (x^2/12) =... (answered by venugopalramana)

x^2/49-y^2/64=1 find the... (answered by ewatrrr)