You want it to look like this



which is a parabola with a horizontal axis of symmetry that
either opens left or right. We can't tell which yet.  It
has a vertex of (h,k)



Get the y-terms on the left and everything else on the right



Divide every term by 4



Complete the square on the left side:

1. To the side, multiply the coefficient of y, which is -1, by ,
   getting 
2. Square the result of 1.  
3. Add the result of 2 to both sides of the equation:



Factor the left side:  
Combine the numbers on the right 



To show the 4p in the standard equation, perhaps your teacher
wants you to put a 1 factor on the right side:



and now it corresponds exactly to



The vertex is (h,k) = (1,)

4p=1, so p=, since p is positive it opens right.

Its focus is the point  unit right of its vertex,
at (1,), and the latus rectum is 4p=1 unit long
through the focus.  The directrix line is the vertical 
line  unit left of the vertex.  It has the 
equation . to 4p = 1 unit. So we draw the 
vertex, focus, directrix and latus rectum and we have this:



Then we sketch in the parabola:



Yes, I know you didn't need to graph it but you'll have to later.

Edwin