SOLUTION: . A conic has focus at (0, 0) and directrix at x = −1. The point (4, 3) lies on the
conic. Hence determine the eccentricity of the conic, and state whether it is an
ellipse
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Question 827611: . A conic has focus at (0, 0) and directrix at x = −1. The point (4, 3) lies on the
conic. Hence determine the eccentricity of the conic, and state whether it is an
ellipse, parabola or hyperbola.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A conic has focus at (0, 0) and directrix at x = −1. The point (4, 3) lies on the conic. Hence determine the eccentricity of the conic, and state whether it is an ellipse, parabola or hyperbola.
***
focus and directrix shows axis of symmetry: y=0, or x-axis
directrix of x=-1 shows conic is a parabola that opens right.
Its basic equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex
p=1/2
4p=2
vertex:(0,-1/2) Eccentricity does not apply to parabolas.
Equation of given conic: y^2=2(x+1/2)
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