SOLUTION: The equation of an ellipse with center (4,3) that passes through the points (8,3) and (4,5) has the form f(x,y)=1. Find f(x,0).

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Question 825585: The equation of an ellipse with center (4,3) that passes through the points (8,3) and (4,5) has the form f(x,y)=1. Find f(x,0).
Found 2 solutions by Edwin McCravy, jsmallt9:
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
We plot those three points:



And now we can sketch the ellipse:



and draw 'a' and 'b'.

We can tell that a=4 and b=2 by counting units:



The equation is

  

  

  

Since   f(x,y) ,

The above graph is a cross section of a 3D eliptic paraboloid, when
sliced at the plane where z=1.  We are to find f(x,0) 

        f(x,y)

and     f(x,0)

        f(x,0)

        f(x,0)

        f(x,0)

That is a parabola which is a cross section of the same 3D elliptic
paraboloid when sliced by the xz-plane.

Edwin


Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
The other tutor's response is excellent. But it does have an error. When f(x, 0) is found, it should be the y, not the x, that gets replaced by zero:

making

Simplifying...



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