SOLUTION: [ Find vertex, focus, and latus rectum axis of a parabola 3x^2 + 12x

SOLUTION: [ Find vertex, focus, and latus rectum axis of a parabola 3x^2 + 12x - 8y = 0 ]

Question 821679: [ Find vertex, focus, and latus rectum axis of a parabola 3x^2 + 12x - 8y = 0 ]
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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3x^2 + 12x - 8y = 0
8y = 3x^2 + 12x
y = 3/8x^2 + 12/8x
y = 0.375x^2 + 1.5x
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the above quadratic equation is in standard form, with a=0.375, b=1.5, and c=0
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
0.375 1.5 0
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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answer:
the quadratic vertex is a minimum at: ( x= -2, y= -1.5 )
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the focus is: ( -2, -0.833333 )
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latus rectum axis is: y= -1.5
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
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