SOLUTION: What are the vertices of 81x^2+9y^2=49

Question 819196: What are the vertices of 81x^2+9y^2=49
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What are the vertices of 81x^2+9y^2=49
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[x^2/(49/81)] + y^2/[49/9] = 1
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[x^2/(7/9)^2] + y^2/[(7/3)^2] = 1
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Center at (0,0)
Vertices on major axis: (0,-7/3) ; (0,+7/3)
Vertices of minor axis: (-7/9,0) ; (7/9,0)
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Cheers,
Stan H.
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