SOLUTION: How to get the standard equation from 9x^2+9y^2-441 and it a circle

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Question 818958: How to get the standard equation from 9x^2+9y^2-441 and it a circle
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius

9x^2+9^y2-441 = 0  |Note the use of ^ (upper case 6)

9x^2+9y^2 = 441    |dividing each term on both sides of the EQ by 9

 x%5E2+%2B+y%5E2+=+49   r = 7