SOLUTION: find the vertex, the focus, and the directrix. then draw the graph x^2-16y=0

Question 816441: find the vertex, the focus, and the directrix. then draw the graph
x^2-16y=0
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x^2 - 16y = 0
(1/16)x^2 - y = 0
y = (1/16)x^2
y = 0.0625x^2
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the above quadratic equation is in standard form, with a=0.0625, b=0, and c=0
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to solve the quadratic equation, plug this:
0.0625 0 0
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the roots of the quadratic are:
x = 0
x = 0
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the vertex is a minimum at: ( 0, 0 )
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the focus is: ( 0, 4 )
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the directrix is: y = -4
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the graph:

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