SOLUTION: Determine the type of curve represented by the equation. Find the foci and vertices (if any). {{{x^2/12 + y = 1}}}

Question 813412: Determine the type of curve represented by the equation. Find the foci and vertices (if any).

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
(1/12)x^2 + y = 1
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y = (-1/12)x^2 + (0)x + 1
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the above quadratic equation is in standard form, with a=(-1/12)=-0.08333333, b=0, and c=1
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to solve the quadratic equation, plug this:
-0.08333333 0 1
into this: https://sooeet.com/math/quadratic-equation-solver.php
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Answer 1:
the vertex of the above quadratic equation is a maximum point: ( 0, 1 )
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Answer 2:
the quadratic equation is a parabola with a single focus at: ( 0, -2.00000012 )
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Solve and graph linear equations:
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