SOLUTION: Find the vertex, focus, and directrix of the parabola. {{{x-y^2+4y-2=0}}}

Question 813136: Find the vertex, focus, and directrix of the parabola.

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertex, focus, and directrix of the parabola.

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x-y^2+4y-2=0
y^2-4y=x-2
complete the square:
(y^2-4y+4)=x-2+4
(y-2)^2=(x+2)
This is a parabola that opens rightwards:
Its basic form of equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex.
vertex:(-2,2)
axis of symmetry:y=2
4p=1
p=1/4
focus:(-7/4,2)
directrix:(-9/4,2)
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