SOLUTION: how to find the radius and the center of circle given this equation; x squared - y squared - 6x-4y-3=0 (x squared - 6x)+6 (y squared- 4y)=3

SOLUTION: how to find the radius and the center of circle given this equation; x squared - y squared - 6x-4y-3=0 (x squared - 6x)+6 (y squared- 4y)=3

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Question 812792: how to find the radius and the center of circle given this equation;
x squared - y squared - 6x-4y-3=0
(x squared - 6x)+6 (y squared- 4y)=3
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
You'll need to re-post your question. The equation you posted here is a hyperbola, not a circle.
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