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Hi,
x^2 +y^2 +6x -2y-6=0 graph the circle
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius
Completing the squares:
x^2 +y^2 +6x -2y-6= (x+3)^2 + (y-1)^2 -9 -1 - 6 = 0
(x+3)^2 + (y-1)^2 = 16
Circle with C(-3, 1) radius 4