Hi,



x^2 +y^2 +6x -2y-6=0  graph the circle

Standard Form of an Equation of a Circle is  

where Pt(h,k) is the center and r is the radius



Completing the squares:

x^2 +y^2 +6x -2y-6= (x+3)^2 + (y-1)^2 -9 -1 - 6 = 0 

                    (x+3)^2 + (y-1)^2 = 16

Circle with C(-3, 1) radius 4 

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