SOLUTION: How do I find the vertex of the following parabola f(x)= -x^2 + 9x -5

Algebra.Com
Question 81128: How do I find the vertex of the following parabola
f(x)= -x^2 + 9x -5

Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
the vertex is on the axis of symmetry; the general equation of which is x=-b/2a ... in this case, x=-9/(-2), or x=4.5

so the x value for the vertex is 4.5 ... to find the y value, just substitute into the equation

... so y=15.25 ... vertex is (4.5,15.25)

RELATED QUESTIONS

Find the vertex of the parabola. f(x) = -x2 + 9x -... (answered by robertb)
how do I find the vertex in fraction form for the following problem:... (answered by Fombitz)
find the coordinates of the vertex of the parabola... (answered by checkley77)
Graph the quadratic function {{{f(x)=-7x^2-10x+5}}}. State the ordered pairs representing (answered by solver91311)
Select the x-coordinate of the vertex of the parabola defined by the function... (answered by josgarithmetic,MathTherapy)
f(x) = -2(x + 1)2 + 5 how to find coordinates of vertex for... (answered by Fombitz)
Question: How do I find the vertex and intercepts for each parabola. g(x)=x^2+x-6... (answered by venugopalramana)
Please help me with this equation how do I work this out? Consider the function {{{f(x) = (answered by jim_thompson5910,nerdybill)
Find the x-intercepts and the vertex of the parabola. f(x) = 4x^2 - 56x +... (answered by ankor@dixie-net.com)