SOLUTION: Find the center of the ellpise below
(x-8)^2/49+(y+6)^2/121=1
Algebra.Com
Question 798893: Find the center of the ellpise below
(x-8)^2/49+(y+6)^2/121=1
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The equation of an ellipse centered at )
and with semi-major axis 
and semi-minor axis 
is either:
^2}{a^2}\ +\ \frac{\left(y\ -\ k\right)^2}{b^2}\ =\ 1)
or
^2}{b^2}\ +\ \frac{\left(y\ -\ k\right)^2}{b^2}\ =\ 1)
It might help to rewrite your equation thus:
^2}{7^2}\ +\ \frac{\left(y\ -\ (-6)\right)^2}{11^2}\ =\ 1)
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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