SOLUTION: Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y

Question 789490: Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Identify the focus, directrix, and axis of symmetry then graph the parabola x^2=-2y
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This is an equation of a parabola that opens down with vertex at the origin.
Its basic form: x^2=-4py
For given parabola:
axis of symmetry: x=0
4p=2
p=1/2
focus: (0,-1/2) (p-distance below vertex on the axis of symmetry)
Directrix: y=1/2 (p-distance above vertex on the axis of symmetry)
see graph below:

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