SOLUTION: I need help on understanding parabolas and how to solve them. The vertex of this parabola is at (-2,-3). When the x-value is -1, the y-value is -5. What is the coefficient of the

Question 775143: I need help on understanding parabolas and how to solve them.
The vertex of this parabola is at (-2,-3). When the x-value is -1, the y-value is -5. What is the coefficient of the squared expression in the parabola's equation?
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
Q:
The vertex of this parabola is at (-2,-3). When the x-value is -1, the y-value is -5. What is the coefficient of the squared expression in the parabola's equation?
---------------------------------------------------------------------
A:
The vertex of parabola (quadratic function) with equation is (h,k).
If the vertex is (-2,-3), then h = -2, k = -3 and the quadratic function is . Substitute x = -1 and y = -5.

-5 = a-3
a = -2
Therefore, OR
The coefficient of the squared expression is .
RELATED QUESTIONS
I really need help on vertex forms and standard form parabolas. I understand how to get... (answered by stanbon)

the vertex of a parabola is at(2,-4). when the x value is 3, the y value is -1. what is... (answered by erica65404)

the vertex of the parabola is at (2,-1).when the y-value is at 0, the x-value is at 5.... (answered by Fombitz)

the vertex of the parabola is at (-2,-3). when the y-value is -2, the x-value is -5. what (answered by Fombitz)

we're doing parabolas at the moment. I need to know how to find the turning point of a... (answered by josgarithmetic)

hello, my question is concerning parabolas. I have to find the equation of the parabola... (answered by stanbon)

The vertex of this parabola is at (1, 2). When the x-value is 0, the y-value is 0. What... (answered by josgarithmetic,Theo,MathTherapy)

Hi i am wondering how to solve for the "p" value in parabolas. from what i understand you (answered by lwsshak3)

Ok, I'm not sure if this problem is in this section but I didn't see a "parabolas" title... (answered by ankor@dixie-net.com)