SOLUTION: What is the focal point of the ellipse (x+3)^2/16 + (y-1)^2/4 ?

Question 769001: What is the focal point of the ellipse (x+3)^2/16 + (y-1)^2/4 ?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the focal point of the ellipse (x+3)^2/16 + (y-1)^2/4 ?
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This is an equation of an ellipse with horizontal major axis.
Its standard form: , a>b, (h,k)=(x,y) coordinates of center
For given ellipse:
center: (-3,1)
a^2=16
b^2=4
c^2=a^2-b^2=16-4=12
c=√12≈3.46 (distance from center to foci on horizontal major axis)
foci: (-3�c, 1)=(-3�3.46,1)=(0.46,1) and (-6.46,1) (note: ellipses have 2 focal points)

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