SOLUTION: Find the focus, directrix, and focal diameter of the parabola. 4x^2 +11y = 0

Question 764024: Find the focus, directrix, and focal diameter of the parabola. 4x^2 +11y = 0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the focus, directrix, and focal diameter of the parabola. 4x^2 +11y = 0
***
4x^2 +11y = 0
4x^2=-11y
x^2=-(11/4)y
This is an equation of a parabola that opens downward.
Its standard form: x^2=-4py
For given equation:
vertex: (0,0)
4p=11/4
p=11/16
focus: (0,11/16)
directrix: y=-11/16
I'm not familiar with the term "focal diameter" unless you mean focal width=4p=11/4

RELATED QUESTIONS
Find the focus, directrix, and focal diameter of the parabola. 9x + 7y2 = 0 focus (x,... (answered by Fombitz)

Find the vertex, focus, directrix, and focal width of the parabola. x2 = 20y choices... (answered by MathLover1,greenestamps)

Find the vertex, focus, directrix, and focal width of the parabola.... (answered by lwsshak3)

Find the vertex, focus, directrix, and focal width of the parabola. -1/40 x^2=... (answered by josgarithmetic)

x=-2y^2 whats the directrix focal diameter, and... (answered by macston)

Find the vertex, focus, directrix, and focal width of the parabola. choices below (5... (answered by MathLover1)

1. Find the standard form of the equation of the parabola with a focus at (0, -9) and a... (answered by josgarithmetic)

1. Find the standard form of the equation of the parabola with a focus at (-4, 0) and a... (answered by josgarithmetic)

Find the vertex, focus, directrix, and focal width of the parabola. Show the graph. {{{... (answered by MathLover1)