SOLUTION: how do i put this hyperbola in to standard form of ((x-h)^2/a^2)-((y-k)^2/b^2)=1 by completing the square 36x^2-y^2-24x+6y-91=0 i know i have to group the x's and y's but when i

Question 760858: how do i put this hyperbola in to standard form of ((x-h)^2/a^2)-((y-k)^2/b^2)=1 by completing the square
36x^2-y^2-24x+6y-91=0
i know i have to group the x's and y's but when i group the x's (36x^2-24x) how do i make 36x^2 just x^2 because i factored out 12 to get 12(3x^2-2x) but the 3 in from of the x^2 is really confusing me please help :( asap Thank youuu

Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!

Now DIVIDE the x expression by 36 and indicate a factor of 36 applied to the x expression.

The missing square term for the x part is
and
The missing square term for the y part is

Watch the signs and factors very carefully when you ADD the square terms to both sides of the equation, because this can be the source of mistakes.
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