SOLUTION: For the ellipse represented by 25x^2 + 16y^2-160y =0 find the center
Algebra.Com
Question 760694: For the ellipse represented by 25x^2 + 16y^2-160y =0 find the center
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
For the ellipse represented by 25x^2 + 16y^2-160y =0 find the center
-------
25x^2 + 16(y^2-10y+25) = 16*25
-------
25(x-0)^2 + 16(y-5)^2 = 400
----
Center at (0,5)
===========================
cheers,
Stan H.
============================
RELATED QUESTIONS
For the ellipse represented by 25x^2 + 16y^2 -160y = 0 find the vertices on major... (answered by stanbon)
Can you show a step by step process of how to put 25x^2+16y^2+150x=160y-225 into standard (answered by MathLover1)
Identify the CONIC(circle,ellipse,hyperbola) and state the center... (answered by scott8148)
Graph the ellipse and find the coordinates of the center vertices and foci.... (answered by Edwin McCravy)
put this conic section in standard form. What is the a^2 value?... (answered by lwsshak3)
Put this conic section into standard form. What is the a^2 value? 25x^2 + 16y^2 + 150x =... (answered by lwsshak3)
is this problem a hyperbola, ellipse or a circle? Solve and show graph... (answered by rwm)
What is the standard form for this conic section?
X^2+16y^2+12x+160y+276=0 (answered by Alan3354)
Find the center, vertices, and foci for the ellipse: 4x^2+16y^2=64... (answered by Nate)