SOLUTION: what are the center and radius of the circle described by the equation (x-5)2+(y+4)2=121?

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Question 759313: what are the center and radius of the circle described by the equation (x-5)2+(y+4)2=121?
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Equation of a circle
(x - a)^2 + (y - b)^2 = r^2
(x-5)2+(y+4)2=121
Centre = (5,-4) radius = 11
Hope this helps.
:-)