SOLUTION: 9x^2-16y^2=144

Question 757927: 9x^2-16y^2=144
Answer by DSMLMD(16) (Show Source): You can put this solution on YOUR website!
9x^2-16y^2=144

divide 144 to the two sides we get:

x^2/16 - y^2/9 = 1

the equation can be written as:

(x-0)^2/16 - (y-0)^2/9 = 1

we get:
h=0
k=0
a^2 = 16 -> a = 4
b^2 = 9 -> b = 3

now, we must find c
c^2 = a^2 + b^2
c^2 = 16 + 9
c^2 = 25
c = 5

foci:
(h�c,k)
(0�5,0)
(-5,0) and (5,0)

vertices:
(h�a,k)
(0�4,0)
(-4,0) and (4,0)

center
(h,k)
(0,0)

asymptotes
y=�b/a(x-h)+k
y=�3/4(x-0)+0
y=�3x/4

it's hyperbola
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