SOLUTION: Find an equation in standard form for a hyperbola whose transverse axis endpoints are (-5,2) and (3,2) and whose conjugate axis has length 6.

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Question 754759: Find an equation in standard form for a hyperbola whose transverse axis endpoints are (-5,2) and (3,2) and whose conjugate axis has length 6.
Answer by lwsshak3(11628) About Me  (Show Source):
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Find an equation in standard form for a hyperbola whose transverse axis endpoints are (-5,2) and (3,2) and whose conjugate axis has length 6.
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Given hyperbola has a horizontal transverse axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (1,2)
length of horizontal transverse axis=8 (-5 to 3)=2a
a=4
a^2=16
length of conjugate axis=6=2b
b=3
b^2=9
Equation of given hyperbola:
%28x-1%29%5E2%2F16-%28y-2%29%5E2%2F9=1