SOLUTION: Find the vertex and the focus of the parabola x^2=-16y.

Question 754645: Find the vertex and the focus of the parabola x^2=-16y.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertex and the focus of the parabola x^2=-16y.
This is an equation of a parabola that opens downward with vertex at (0,0)
Its basic form: x^2=-4py
For given equation:
Axis of symmetry: x=0
4p=16
p=4
focus: (0,-4) (p-distance below vertex on the axis of symmetry)
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