Question 754088: How do you graph this equation(parabola) and identify the vertices, the foci, and the center? I'm confused on the steps
(x+4)^2 = 16(y+1) Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! How do you graph this equation(parabola) and identify the vertices, the foci, and the center? I'm confused on the steps
(x+4)^2 = 16(y+1)
Given equation is that of a parabola that opens upward.
Its basic equation: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
For given equation:
vertex: (-4,-1)
axis of symmetry: x=-4
4p=16
p=4
focus: (-4,3) (p-distance above vertex on the axis of symmetry)
note: (parabolas have only one focus and no center)
see graph below:
y=(x+4)^2/16-1
(