SOLUTION: what is the equation of the parabola whose vertex = (4,-6) and focus is (6, -6)

Question 754005: what is the equation of the parabola whose vertex = (4,-6) and focus is (6, -6)
Answer by DSMLMD(16) (Show Source): You can put this solution on YOUR website!
Vertex (4,-6) and Focus at (6,-6)

Because the y-vertex and y-focus is same, the equation of parabola is:
(y - b)^2 = 4p(x - a)

Vertex:
(4,-6)
(a,b)

Focus Point:
(6,-6)
((p+a),b)

If
b = -6
a = 4

then,
p + a
6 = p + 4
2 = p

the parabola equation is:
(y - b)^2 = 4p(x - a)
(y - (-6))^2 = 4(2)(x - 4)
(y + 6)^2 = 8(x - 4)
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