SOLUTION: i need help finding the center, coverticies, focis of this equation (x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?

Question 753292: i need help finding the center, coverticies, focis of this equation (x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
finding the center, coverticies, focis of this equation:
(x+1)^2/16-(y-2)^2/49=1 h=? k=? a=? b=? c=?
(x+1)^2/16-(y-2)^2/49=1
This is a hyperbola with horizontal transverse axis>
Its standard form of equation:, (a,b)=(x,y) coordinates of center
For given equation:
center: (-1,2)
a^2=16
a=4
b^2=49
b=7
co-vertices:(-1,2�b)=(-1,2�7�=(-1,9) and (-1,-5)
c^2=a^2+b^2=16+49=65
c=√65≈8.06
foci::(-1,2�c)=(-1,2�8.06�=(-1,10.06) and (-1,-6.06)
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