SOLUTION: fine equation of the ellipse which had eccentricity of 3/4 and its equation of directrix is y= +-16/3

Question 752405: fine equation of the ellipse which had eccentricity of 3/4 and its equation of directrix is y= +-16/3
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find equation of the ellipse which had eccentricity of 3/4 and its equation of directrix is y= +-16/3
***
given ecccentricity,e=3/4
center:(0,0)
ellipse has a vertical major axis:
Its standard form of equation:, a>b
ae=directrix=�16/3
a=(16/3)/(3/4)
a=4
a^2=16
c^2=a^2-b^2
e=c/a
c=ae=4*3/4=3
b^2=a^2-c^2=16-9=7
Equation of given ellipse:

RELATED QUESTIONS
Find a polar equation of an ellipse with its focus at the pole, an eccentricity of e... (answered by MathLover1)

determine the standard equation of the ellipse that has the ends of its minor axis at... (answered by lwsshak3)

Find the equation of ellipse with centre (1, 4),vertex at (1,7) and eccentricity e= 2/3.... (answered by ikleyn)

Find a polar equation of a hyperbola with its focus at the pole, an eccentricity of e... (answered by MathLover1)

use the eccentricity of each hyperbola to find its equation in standard form... (answered by lwsshak3)

construct an ellipse when the distance of its focus from its directrix is equal to 60 mm (answered by stanbon)

write the equation of conic with eccentricity e,focus(a,0) and directrix y-axis... (answered by fractalier)

a hyperbola of eccentricity 3/2 has one focus at (1,-3). The corresponding directrix is... (answered by Edwin McCravy)