SOLUTION: What are the center and radius of the circle whose equation is x2 + (y-3)2 = 144?

SOLUTION: What are the center and radius of the circle whose equation is x2 + (y-3)2 = 144?

Algebra.Com

Question 751914: What are the center and radius of the circle whose equation is x2 + (y-3)2 = 144?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
x^2 + (y - 3)^2 = 144
Multiply out the bracket.
x^2 +(y^2 - 6y + 9) = 144
x^2 + y^2 - 6y + 9 - 144 = 0
x^2 + y^2 -6y - 135 = 0
Centre (0, 3) radius =sqrrt 0^2 + 3^2 + 135
= sqrrt 144
= 12
Hope this helps.
:-)
RELATED QUESTIONS
What are the coordinates of the center and the measure of a radius of the circle whose... (answered by Boreal)

Find the center-radius form of the circle whose equation is x2 + 6x + y^2 - 2y + 6 =... (answered by mananth)

What is the center and radius of the circle with the given equation... (answered by rfadrogane)

. Find the center and radius of the circle whose equation is x2 + y2 � 4 = 0. (answered by Alan3354)

Classify the conic section: 1. x2 + y2 = 36 2. x2 - y2 = 36 3. 5x2 +... (answered by Edwin McCravy)

find the center and radius of a circle whose equation is... (answered by stanbon)

find the center and the radius of the circle whose equation is (x-3)^2 + (y+2)^2 = 16 (answered by Fombitz)

The equation of the circle whose center is at (2, 1) and radius is 3... (answered by ewatrrr)

15. What are the center and radius of the circle whose equation is x^2 + (y-3)^2 = 144? (answered by checkley77)