SOLUTION: How do I write equation for each conic section: Circle with center at (0 ,-3) and the radius of 5 Parabole with Vertex at (-3,5) and focus at (-1,5) Ellipse with the vertic

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How do I write equation for each conic section: Circle with center at (0 ,-3) and the radius of 5 Parabole with Vertex at (-3,5) and focus at (-1,5) Ellipse with the vertic      Log On


   



Question 750757: How do I write equation for each conic section:
Circle with center at (0 ,-3) and the radius of 5
Parabole with Vertex at (-3,5) and focus at (-1,5)
Ellipse with the vertices at (2,5) (2,-3) and co-vertices at (0,1) (4,1)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do I write equation for each conic section:
Circle with center at (0 ,-3) and the radius of 5
Standard form of equation for a circle: %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2, (h,k)=center, r=radius
For given circle:
center: (0,-3)
radius=5
x%5E2%2B%28y%2B3%29%5E2=25
..
Parabola with Vertex at (-3,5) and focus at (-1,5)
Parabola opens rightward:
axis of symmetry: y=5
Its basic equation: %28y-k%29%5E2=4p%28x-h%29%5E2, (h,k)=(x,y) coordinates of vertex
For given parabola:
p=2(distance from vertex to focus on the axis of symmetry
4p=8
Equation:%28y-5%29%5E2=8%28x%2B3%29
..
Ellipse with the vertices at (2,5) (2,-3) and co-vertices at (0,1) (4,1)
Given ellipse has a vertical major axis
Its standard form of equation: %28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, a>b, (h,k)=(x,y) coordinates of center
For given ellipse:
x-coordinate of center=2
y-coordinate of center=1 (midpoint of vertex)
center: (2,1)
a=4 (distance from center to vertices)
a^2=16
b=2(distance from center to co-vertices)
b^2=4
Equation of given ellipse: %28x-2%29%5E2%2F4%2B%28y-1%29%5E2%2F16=1