SOLUTION: write an equation of the conic/parabola with vertex at (-4,3) and focus at (-4,-2). I'm having trouble with this section of math and it would be great if you could help me. thank y

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: write an equation of the conic/parabola with vertex at (-4,3) and focus at (-4,-2). I'm having trouble with this section of math and it would be great if you could help me. thank y      Log On


   



Question 750606: write an equation of the conic/parabola with vertex at (-4,3) and focus at (-4,-2). I'm having trouble with this section of math and it would be great if you could help me. thank you.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The focal length is abs%283-%28-2%29%29=5. You should reread the book discussion about deriving the equation for a parabola. if p is the focal length, then a standard position parabola is 4py=x%5E2, or y=%281%2F%284p%29%29x%5E2.

You should use the standard form for a parabola, since you know your vertex, as given (-4,3). Putting this information into the standard form equation, you have y=%281%2F%284p%29%29%28x%2B4%29%5E2%2B3
and because you know p=5, the focal length,
y=%281%2F%284%2A5%29%29%28x%2B4%29%5E2%2B3
highlight%28y=%281%2F20%29%28x%2B4%29%5E2%2B3%29

You can leave in standard form, or you can multiply and simplify the right hand side into general form.



*____Note that the standard form equation for a parabola is y=a%28x-h%29%5E2%2Bk where the vertex is (h,k).