SOLUTION: parabola with vertex at (-3,1) and directrix x=-8

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Question 75003This question is from textbook algebra II
: parabola with vertex at (-3,1) and directrix x=-8This question is from textbook algebra II

Answer by stanbon(48569) About Me  (Show Source):
You can put this solution on YOUR website!
parabola with vertex at (-3,1) and directrix x=-8
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Distance from (-3,1) to x=-8 = -3--8=5
Therefore p=5
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Plot the vertex and the directrix and you will see the
parabola opens to the right:
So the form is (y-k)^2=4p(x-h)
EQUATION:
(y-1)^2 = 4*5(x+4)
(y-1)^2= 20x+80
x = (1/20)(y-1)^2-4
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Cheers,
Stan H.