SOLUTION: i need to know how to get y^2-12y-x^2-2x= -31 in standard form

Question 733704: i need to know how to get y^2-12y-x^2-2x= -31 in standard form

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y^2-12y-x^2-2x= -31 in standard form
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Complete the square on the x-terms and on the y-terms.
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y^2 - 12y + (12/2)^2 - (x^2 + 2x + (2/2)^2) = -31 + (12/2)^2 - (2/2)^2
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Factor:
(y-6)^2 - (x+1)^2 = 4
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[(y-6)^2 / 4] - [(x+1)^2/ 4] = 1
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Cheers,
Stan H.
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