SOLUTION: 5y^2-4x^2=20 in vertex form
Algebra.Com
Question 732490: 5y^2-4x^2=20 in vertex form
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
y=a(x-h)^2+k
RELATED QUESTIONS
5y^2-4x^2=20
What is the vertex form?
What is the type of conic?
What is the... (answered by MathLover1)
3x^2-7x-20 in vertex... (answered by robertb)
Write y=-4x^2+8x-1 in vertex form.
(answered by stanbon)
write the function f(x)=4x^2-48x-141 in vertex form, and identify its vertex
(answered by haileytucki)
5x^2+5y^2-20=0 in standard... (answered by lwsshak3)
-4x+5y=20 in y-intercept form and... (answered by mananth)
Write in vertex form. Sketch a graph of the function and label its vertex.
1. y = x^2 + (answered by Fombitz)
Rewrite the equation y=–2x^2-4x+3 in vertex form. Identify the vertex and the axis of... (answered by ewatrrr)
Write the quadratic function in vertex form and then find the vertex:
y=x^2+4x+7... (answered by Alan3354)