SOLUTION: find the vertex, focus, and directrix. Then draw the graph 1), {{{x^2+6x=8y-1}}} 2), {{{y=(1/16)*(x+1)^2 -2}}}

Question 732375: find the vertex, focus, and directrix. Then draw the graph
1),
2),
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Here is a bit of help on your question number 2.

When you derive the equation for a general parabola through distance formula and directrix and focus, you get a result of , and p is the distance from the vertex to the focus and it is also the distance from the vertex to the directrix.

The shape of your parabola in #2 is the same shape as , only the position has changed. Compare this with the general equation for the untranslated equation for a parabola. You can get the value of p through equating 4p with (1/16). .

As for the vertex, look for the information from the given equation (which is already given in standard form) to find the "(h, k)" point.
You have , so your vertex is (-1, -2).
If you did not yet find p, do it NOW. You are ready to find the focus [(-1, -2+p)] and the directrix.
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