SOLUTION: What is the equation of the ellipse in standard form? 9x^2+16y^2-18x-64y-71=0

SOLUTION: What is the equation of the ellipse in standard form? 9x^2+16y^2-18x-64y-71=0

Algebra.Com

Question 730986: What is the equation of the ellipse in standard form?
9x^2+16y^2-18x-64y-71=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the equation of the ellipse in standard form?
9x^2+16y^2-18x-64y-71=0
***
9x^2-18x+16y^2-64y=71
complete the square:
9(x^2-2x+1)+16(y^2-4y+4)=71+9+64
9(x-1)^2+16(y-2)^2=144

RELATED QUESTIONS
Find the center of an ellipse with the equation {{{9x^2 + 16y^2 - 18x + 64y =... (answered by mukhopadhyay)

Find the center of an ellipse with the equation {{{9x^2 + 16y^2 - 18x + 64y =... (answered by Edwin McCravy)

Find the center of an ellipse with the equation... (answered by Fombitz)

find the center of an ellipse with the equation 9x^2+16y^2-18x+64y=71 Find the foci... (answered by jsmallt9)

What is the standard form of 9x^2- 16y^2 -18x + 96y -... (answered by ewatrrr)

9x^2 + 16y^2 - 18x + 64y - 71 = 0 find the coordinates of the center. a)(1,2)... (answered by RAY100,crystal_nguyen)

Find the center,foci,vertices and covertices of the ellipse with the given equation.... (answered by ikleyn)

Determine the center,foci,vertices,and covertices of the ellipse with the given equation: (answered by KMST)

16y^2-9x^2+18x+64y-89=0 (answered by Edwin McCravy)