SOLUTION: y=1/4xsquared Find the vertex, focus, and directrix. Steps to graph the parabola.

Question 729989: y=1/4xsquared Find the vertex, focus, and directrix. Steps to graph the parabola.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
y=1/4xsquared Find the vertex, focus, and directrix. Steps to graph the parabola.
***
y=x^2/4
x^2=4y
this is a parabola that opens upward
Its basic form of equation: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex.
For given equation:x^2=4y:
vertex:(0,0)
axis of symmetry: x=0 or y-axis
4p=4
p=1
focus: (0,1) (p-distance above vertex on the axis of symmetry)
directrix: y=-1 (p-distance below vertex on the axis of symmetry)
To graph the curve, plug in small x-values like �2 to get two points on the curve.
With coordinates of the vertex and these 2 points you can draw the graph.

RELATED QUESTIONS
Find the vertex, focus, and directrix of the parabola. Graph the equation. y^2 - 2y =... (answered by lwsshak3)

Find the vertex, focus, directrix, and focal width of the parabola. Show the graph. {{{... (answered by MathLover1)

parabola,x^2 +6x -y +11 =0 find the vertex,focus and directrix of the... (answered by lwsshak3)

Find the vertex, focus and directrix of the parabola and sketch the graph... (answered by josgarithmetic)

Find the vertex, the focus, and the directrix of the parabola. 1) y = x2 + 9x + 20 (answered by lwsshak3)

x^2+8x-y+6=0 Find the vertex, focus, and directrix of the parabola. Sketch the... (answered by Nate)

Find the vertex, focus, directrix, and focal width of the parabola. -1/40 x^2=... (answered by josgarithmetic)

PARABOLA: what's the vertex, focus, directrix, latus rectum and graph of the... (answered by solver91311)

Find the equation of the parabola described: Focus at (0,2); vertex at (0,0). Graph the... (answered by MathLover1)