SOLUTION: y=3/5x^2+30x=282 in vertex form

SOLUTION: y=3/5x^2+30x=282 in vertex form

Algebra.Com

Question 725333: y=3/5x^2+30x=282 in vertex form
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
y=3/5x^2+30x=282 in vertex form
complete the square:
y=3/5(x^2+50x+625)=282+375
y=(3/5)(x+25)^2-657
This is an equation of a parabola that opens upward:
Its standard (vertex) form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
RELATED QUESTIONS
Write the quadratic equation in vertex form. What is the vertex?... (answered by MathLover1,stanbon)

Find the vertex,focus,and directrix in the given parabola equation.:... (answered by josgarithmetic)

Write f(x)=-5x^2-60x-181 in vertex form and identify the... (answered by stanbon)

Write the function f(x)=-5x^2-60x-181 in vertex form, and identify its... (answered by josgarithmetic,ikleyn)

convert the standard parabolic equation y = 3x ^2 - 30x - 7 to vertex form. (answered by MathLover1)

Rewrite the following quadratic function in vertex form. Then, determine the axis of... (answered by josgarithmetic)

Write the equation in vertex form. Identify the vertex.... (answered by josgarithmetic)

x2(squared)+5x-24 in vertex... (answered by jim_thompson5910)

A.Find the equation of the quadratic function in standard form vertex (0, 18) ; passing (answered by ewatrrr)