SOLUTION: Identify the focus and the directrix for the following parabola: x-3y^2=0

Question 722000: Identify the focus and the directrix for the following parabola:
x-3y^2=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Identify the focus and the directrix for the following parabola:
x-3y^2=0
-3y^2=x
y^2=-(1/3)x
This is an equation of a parabola that opens leftward.
Its basic equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex.
For given parabola:
vertex:(0,0)
axis of symmetry: y=0 or x-axis
4p=1/3
p=1/12
focus: (-(1/12),0) (p-distance to the left of vertex on the axis of symmetry)
directrix: x=1/12 (p-distance to the right of vertex on the axis of symmetry)
RELATED QUESTIONS
Identify the focus, directrix, and axis of symmetry of the parabola... (answered by KMST)

identify the focus and the directrix of each parabola -5y^2 - x... (answered by lwsshak3)

graph the parabola and identify the vertex, focus, directrix:... (answered by lwsshak3)

Identify the focus and directrix of the parabola y=-15x^2, 6x^2-3y=0,... (answered by ewatrrr)

Identify the vertex, focus, and directrix of the parabola.... (answered by stanbon)

Identify the focus, directrix, and axis of symmetry then graph the parabola... (answered by lwsshak3)

Draw the parabola. Identify the focus and directrix and show them on the graph.... (answered by lwsshak3)

Identify the vertex, focus and directrix of the parabola with the equation... (answered by ewatrrr,lwsshak3)

Identify the vertex, focus, and directrix of the parabola with the equation... (answered by ewatrrr)