SOLUTION: Give the focus, directrix, and axis for the parabola. {{{ (x-7)^2=16(y+5) }}}

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Give the focus, directrix, and axis for the parabola. {{{ (x-7)^2=16(y+5) }}}      Log On


   

Question 721910: Give the focus, directrix, and axis for the parabola.
+%28x-7%29%5E2=16%28y%2B5%29+
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Give the focus, directrix, and axis for the parabola.
+%28x-7%29%5E2=16%28y%2B5%29+
***
(x-7)^2=16(y+5)
This is an equation of a parabola that opens upward:
Its basic form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
For given equation:
vertex: (7,-5)
axis of symmetry: x=7
4p=16
p=4
focus: (7,-1) (p-distance above vertex on the axis of symmetry)
directrix: y=-9 (p-distance below vertex on the axis of symmetry)