SOLUTION: Please help Transform to standard form and describe the graph of each equation. 1. 4x²+1=-4y²+4y 2. 36x²+36y²+36y=48x+199 3. 9x²+9y²+6x=-5 4. 3x²-5y=24-3y²-40 5. x²+y²+3x-5y+1

Algebra.Com
Question 718034: Please help Transform to standard form and describe the graph of each equation.
1. 4x²+1=-4y²+4y
2. 36x²+36y²+36y=48x+199
3. 9x²+9y²+6x=-5
4. 3x²-5y=24-3y²-40
5. x²+y²+3x-5y+17/2=0
thank you

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Those are all equations of circles and they are all done the same way,

I'll do the 2nd one as it is the most complete and the 3rd one is weird:

2. 36x²+36y²+36y=48x+199

Get the x-term next to the x² term and the y-term next to the y² term.
Get only the constant term on the right.

36x²-48x + 36y² + 36y = 199 

Divide every term through by the common coefficient of the x²
and the y² terms, which is 36

x² - x + y² + y = 

Reduce the fraction  to 

x² - x + y² + y = 

Complete the squares on the lft:

1. Multiply the coefficient of x, which is , by ,
getting .
2. Square this result, getting  = 
3. Add this right after the x term on the left side and also 
add it to the right side.

1. Multiply the coefficient of y, which is 1, by ,
getting .
2. Square this result, getting  = 
3. Add this right after the y term on the left side and also 
add it to the right side.

x² - x +  + y² + y +  =  +  + 

Factor the first three terms as (x - )(x - ) which can be
written as the square (x - )².

Factor the last three terms on the left as (y - )(y - ) which can be 
written as the square (y - )².

Combine the terms on the right by getting an LCD of 36
 +  +  =  +  +  =  =  = 

(x - )² + (y - )² = 

That is a circle with center (,) and radius .

----------------------------------

9x²+9y²+6x=-5

Get the x-term next to the x² term and the y-term next to the y² term.
The constant term is already on the right.

9x² + 6x + 9y² = -5

Divide every term through by the common coefficient of the x²
and the y² terms, which is 9:

x² - x + y² = 

Reduce the fraction  to 

x² - x + y² = 

Complete the squares on the left:

1. Multiply the coefficient of x, which is , by ,
getting .
2. Square this result, getting  = 
3. Add this right after the x term on the left side and also 
add it to the right side.

Since there is no y term, write y² as (y - 0)²

x² - x +  + (y - 0)² =  + 

Factor the first three terms as (x - )(x - ) which can be
written as the square (x - )².

Combine the terms on the right:
 +  = 

(x - )² + (y - 0)² = 

That is an imaginary circle with a real center of (,0) and an imaginary
radius of i.  Really weird.  Was that -5 on the right supposed to be 5?


Edwin

----------------------------------

RELATED QUESTIONS

conics 9x^2-36x-4y^2-36y-36=0 could you put this in standard form and show me... (answered by stanbon,Edwin McCravy)
Transform the equation to standard form, then give the coordinates of the center and the... (answered by josgarithmetic)
I have two equations that I cant seem to solve because I dont understand. I have been... (answered by jim_thompson5910)
WW 1.3 Determine whether the equation is a circle or parabola and transform the... (answered by math_tutor2020,josgarithmetic)
I would really appreciate it if you could help me with this question!!! the directions... (answered by josgarithmetic)
Find the foci for each equation. 1) 4x^2 + 9y^2 = 36 2) 36x^2 + 4y^2 = 144 3) 36x^2 (answered by robertb)
Please help me. transform this general form into standard form. 4x^2+4y^2+12x-8y+25... (answered by josgarithmetic)
Please decide whether or not the equation has a circle as its graph. If it does, give... (answered by Fombitz,aarontivey)
For each of the ff. quadratic equations, (a) identify the conic section represented (b)... (answered by khwang)