SOLUTION: if two circles are tangent to each other.one equation of acircle is 3(xsquare)+2(ysquare)+k=0 and the other is 2(xsquare)+3(ysquare)+x+6y=0.then what is the value of k?

Question 709708: if two circles are tangent to each other.one equation of acircle is 3(xsquare)+2(ysquare)+k=0 and the other is 2(xsquare)+3(ysquare)+x+6y=0.then what is the value of k?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
if two circles are tangent to each other.one equation of acircle is 3(xsquare)+2(ysquare)+k=0 and the other is 2(xsquare)+3(ysquare)+x+6y=0.then what is the value of k?
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3x^2 + 2y^2 + k = 0
2x^2 + 3y^2 + x + 6y = 0
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Those are not circles, they're ellipses.
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