SOLUTION: graph the circle x^2+ y^2-6x+4y-3=0
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Question 708177: graph the circle x^2+ y^2-6x+4y-3=0
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Complete the square for both variables and convert the equation to standard form; from this you can read the point (h,k) for center of the circle, and read the radius value.
Given: x^2+ y^2-6x+4y-3=0
The missing square for the x part is (6/2)^2=3^2=9
The missing square for the y part is (4/2)^2=4
The center is at (3,-2) and radius is 4 units.
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