SOLUTION: write the equation for the graph with vertex (-6,3) and focus (-6,0.25). a. (x+6)^2=11(y-3) c. (y-3)^2=-11(x+6) b. (x+6)^2=-11(y-3) d. (y+6)^2=-11(x-3)

Question 698407: write the equation for the graph with vertex (-6,3) and focus (-6,0.25).
a. (x+6)^2=11(y-3) c. (y-3)^2=-11(x+6)
b. (x+6)^2=-11(y-3) d. (y+6)^2=-11(x-3)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
write the equation for the graph with vertex (-6,3) and focus (-6,0.25).
This is a parabola that opens downwards.
Its standard form of equation: (x-h)^2=-4p(y-k), (h,k)=coordinates of vertex
Given vertex: (-6,3)
Axis of symmetry: x=-6
given focus:(-6,0.25)
p=3-.25=2.75 (distance from vertex to focus on the axis of symmetry)
4p=11
Equation: (x+6)^2=-11(y-3) (ans. d)
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