SOLUTION: What is the radius of the circle given by the equation below? x^2 + 8x = -y^2 - 16y

SOLUTION: What is the radius of the circle given by the equation below? x^2 + 8x = -y^2 - 16y - 16

Question 696352: What is the radius of the circle given by the equation below?
x^2 + 8x = -y^2 - 16y - 16
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the radius of the circle given by the equation below?
x^2 + 8x = -y^2 - 16y - 16
**
Standard form of a circle: , (h,k)=(x,y) coordinates of center, r=radius.
To find the radius of given circle, convert given equation to standard form.
x^2 + 8x = -y^2 - 16y - 16
complete the square:
x^2+8x=-y^2-16y-16
x^2+8x+y^2+16y=-16
(x^2+8x+16)+(y^2+16y+64)=-16+16+64

r^2=64
r=8
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