SOLUTION: What are the vertices of the hyperbola given by [(y-1)^2/4]-[(x-2)^2/16]=1?

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Question 694602: What are the vertices of the hyperbola given by [(y-1)^2/4]-[(x-2)^2/16]=1?

Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
 = 1

It's in the form

 = 1

The center is (h,k) = (2,1)

Because the term in y comes first, it's a hyperbola like this .

Therefore the vertices are "a" units above and below the center.

So they are (2,1±2), that is, (2,-1) and (2,3) 

Edwin


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