SOLUTION: (y-7)^2=16(x+5)
how do I make this a y= equation for a parabola?
Algebra.Com
Question 691447: (y-7)^2=16(x+5)
how do I make this a y= equation for a parabola?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(y-7)^2=16(x+5)
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You don't.
It's an "x=" parabola.
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x = (1/16)(y-7)^2-5
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It opens to the right from vertex (7,-5)
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Cheers,
Stan H.
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