SOLUTION: Write an equation for the ellipse Eccentricity 3/4; foci (0,-2) (0,2)

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Question 683687: Write an equation for the ellipse
Eccentricity 3/4; foci (0,-2) (0,2)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation for the ellipse
Eccentricity 3/4; foci (0,-2) (0,2)
This is an ellipse with vertical major axis.
its standard form of equation: %28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, a>b, (h,k)=(x,y) coordinates of center
For given ellipse:
center: (0,0)
c=2 (center to focus)
c^2=4
eccentricity:=3/4=c/a
a=4c/3=16/3
a^2=256/9
c^2=a^2-b^2
b^2=a^2-c^2=256/9-4=256/9-36/9=220/9
Equation:
9x%5E2%2F220%2B9y%5E2%2F256=1